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Ask The Wizard #31

Has anyone researched the best betting techniques for \"Let It Ride\" with added insights? Casinos claim that players should not observe each other’s hands, yet it appears that many players are aware of the holdings of at least two others. I may consider aiming for an inside straight if I can confirm that at least six of the cards are not useful to me.

Brian from Stafford, Virginia

Indeed! In the book Mastering the Game of Let It Ride by Stanley Ko, there's a section dedicated to this subject. Ko discusses how the probability shifts if you possess a 4-card straight or flush while having access to additional cards. Notably, he doesn't mention adjustments at the three-card phase of the game. You can find this booklet at that Gambler's Book Club .

Hello there, great resource you have! I was curious if you happen to have the House Odds for a game called \"Catch A Wave\" that is played at Foxwoods in Connecticut.

Ken L. from Boston, USA

Ask away, and you shall receive an answer. Please refer to my page on Catch a Wave .

Is my boyfriend cheating on me?

Melevinna from IA City, USA

How can I be certain? However, it's important not to jump to conclusions without solid evidence to support your claims.

My inquiry concerns the strategy employed by Norman Leigh in the 1960s to outsmart the bank in Nice. His team used a reverse Labouchere system, which entails absorbing several small losses before landing a significant win. The premise is that rather than canceling out wins, they are added to the sequence while losses are crossed out, ensuring that every gamble is capped at a fixed loss amount but can yield a win up to the table limit. Aside from Norman's publication (and those inspired by it), I've yet to come across any thorough evaluation of this approach. The book claims that this method turns the house edge against itself, leading to a favorable outcome for the player in the long term. Is that a fallacy or is there merit to this concept?

Billy

If they did win, it was purely due to chance, not because of a viable system. As I have reiterated many times, any approach based on a game with negative expectations cannot ultimately surpass the house edge over time nor can it even make a dent in it.

To start, I want to commend you on your fantastic website! I advise everyone I know to check out your site before engaging in any gambling. My question pertains to Three Card Poker, specifically the ante and play format. If you are aware of one of the dealer's three cards, how should that influence your standard strategy? Is it possible to gain an edge over the house, and if so, to what extent?

G.M. from Monmouth County, New Jersey

Please see my hole carding Following the strategy for Three Card Poker, you can actually gain a 3.48% edge!

Regarding the 5% commission on buy bets and lays, how would the odds be affected if there was a charge of $1 for bets between $20-$39, $2 for $40-$59, $3 for $60-$79, and $4 for $80-$99 without any rounding? Your insights are remarkable.

Bry from Chesterton, USA

I appreciate the kind words. The formula used to estimate the house edge in buy and lay bets is the commission amount divided by the total of the bet plus the commission. For the best scenario, betting $39 incurs a $1 commission, giving a house edge of 1/40 = 2.5%. If you can lay $78 to win $39 on the 4 and 10, while still only paying $1, the house edge would be 1/79=1.27%. I’ll leave it to you to work out the other scenarios; I wasn’t fond of when my math textbooks would do that, either.

Is there a way to generate income from playing solitaire in Las Vegas?

Pattie from Arlington, USA

I haven't come across any instances of solitaire being played for money in Vegas. My understanding is that in the early days of Las Vegas, players would bet on the traditional Klondike variant of solitaire, but beyond that, I don't have any further information.

Generally, when wagering on anything that offers even odds, is there a particular strategy or system that could potentially enhance the chances of winning or the payouts?

JJ from Boston, USA

No.

What are the odds of achieving a three pair in Pai Gow Poker? Are those odds more favorable or less than those of getting three of a kind?

Alex from Long Beach, Mississippi

When excluding a three of a kind and two pairs, here are the methods for achieving a three pair along with their respective combination counts.

No wild card: combin(13,3)*10*63*4 =2471040
If a wild card is used to form a pair of aces: combin(12,2)*10*62*42= 380,160
If a wild card is utilized as a singleton ace: combin(12,3)*63= 47,520

The overall figure for the combinations totals 2,898,720. This number is less than half of the 7,470,676 combinations for a three of a kind.

I've observed some newer video slot machines (like Money to Burn, High Bid, Money for Nothing, Who Dun It, etc.) that significantly differ from traditional three-reel machines. First of all, these machines feature five reels. Typically, you can place bets on 1 to 9 pay-lines (although some models offer up to 15 pay-lines), and you can also bet multiple coins per line. For example, betting on nine pay-lines at five coins per line results in a total wager of 45 coins (even betting nickels can accumulate quickly!). Most payouts are multiples of the line bet, though some bonus winnings pay out on the total amount wagered. Is it more beneficial to always wager on all available pay-lines, or is there a particular combination that yields the best return? I have a hunch that the odds of achieving a winning combination on any specific pay-line are equal, but I'm interested to hear if you have additional insights.

Scott from Leawood, USA

Each frame in these video slots has an equal probability of producing any given combination. Therefore, the returns remain consistent regardless of how many coins are wagered.

Could you possibly share your thoughts on the practice of casinos changing dealers? It frequently seems to occur when a table is on a winning streak, and suddenly the casino introduces a new dealer. Before long, players start to experience losses. Do you believe that certain dealers might have a significant impact on the casino's advantage?

Hobbes from Toronto, Canada

Casinos change dealers out of necessity when someone needs to take a break or leave for the day. The act of switching dealers does not alter the odds for players, unless the player is card counting and the game involves a single or double deck; in that case, a new dealer means a fresh shuffle.

How many numbers does the Random Number Generator (RNG) select for each spin on a slot machine? Is it three numbers (one for each reel), or just a single number that corresponds to a unique combination of symbols across all three reels?

Vincent from Chicago, Illinois

The slot machine generates one number for every reel.

Fantastic site, Mike! I've often heard the term \"binomial distribution\" bandied about in gambling discussions. Would you mind providing me with an explanation of what it entails? Thanks ahead of time.

Dennis from Toronto, Ontario

I appreciate the praise. Any introductory book on probability and statistics should adequately cover the topic of binomial distribution. In short, the binomial distribution reflects the likelihood of a specified number of events occurring, given a certain probability for each event and a predetermined number of trials. When the probability of a success is expressed as p, the number of successes as s, and the total number of trials as n, the probability of achieving s successes can be determined as p * combin(n,s). The combin function is elaborated in mys* (1-p)n-s. For instance, if you wish to determine the odds that during 100 spins of a roulette wheel, the outcome will yield exactly 60 reds, the binomial distribution would indicate that the probability is (18/38) glossary Excel features a function dedicated to the binomial distribution as well: =BINOMDIST(x,n,p,0), where:60* (20/38)40* combin(100,60) = 0.003291.

p denotes the probability of a success in any individual trial.

x=number of positive trials. n=total number of trials. To obtain the exact probability for x wins, enter a 0 in the fourth position of the function. Conversely, for the probability of x wins or fewer, use a 1.

In the roulette instance mentioned earlier, the function would be expressed as =BINOMDIST(60,100,18/38,0)

I recently finished your section on craps strategies, and I found it incredibly informative. I understand that combining pass line and come bets with full odds is a solid approach. My question, though, is whether the house edge varies at all when utilizing a strategy involving the pass line with full odds and making up to two come bets with maximum odds? Specifically, how does the number of rolls over time and increasing risk impact these odds, if at all? Should individuals opt for just a single bet with full odds instead? This strategy seems quite popular among knowledgeable players I've encountered at the dice tables.

The house edge remains consistent regardless of the number of come bets you place, provided you consistently take the maximum odds permissible and keep the odds active during the come-out roll. The number of come bets you choose to make should depend on your personal preferences.

Jim from Yakima, USA

This involves mathematically accurate strategies and insights for various casino games such as blackjack, craps, roulette, and many others.