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Ask The Wizard #302

In a matchup of two players in Texas Hold 'Em, which hand stands the highest chance against a pair of Aces of any suit?

Mike B.

Assuming both players see all the way to the river, I've found that the strongest competing hand is a suited 5-6. If the suited cards are not represented in the Ace pair, the potential outcomes are:

  • Win: 22.87%
  • Tie: 0.37%
  • Lose: 76.76%


If the suited cards are included in the pair of Aces (reducing the chance of a flush), the potential outcomes change to:

  • Win: 21.71%
  • Tie: 0.46%
  • Lose: 77.83%


Overall, the possible outcomes are:

  • Win: 22.290%
  • Tie: 0.415%
  • Lose: 77.295%


The Hot Roll bonus feature on slot machines grants players a specific number of coins based on the sum of two dice. Players continue to accumulate coins until they roll a total of seven, which concludes the bonus round. If a seven is rolled on the first attempt, players earn a consolation prize of 70 coins. Here are the rewards for totals other than seven:

  • 2 or 12: 1,000
  • 3 or 11: 600
  • 4 or 10: 400
  • 5 or 9: 300
  • 6 or 8: 200


I'm curious, what would the average bonus win amount to?

anonymous

Press the button below to find the answer.

The answer is 1983.33.

Press the button below to view the solution.

Let x represent the answer. Provided the player doesn't roll a seven, they can always anticipate further winnings of x, in addition to their prior winnings. Essentially, this demonstrates a memory-less characteristic of dice rolling: regardless of how many times you've rolled already, your chance of hitting a seven remains unchanged from the beginning.

Rather than delving into the fundamentals of dice probabilities, I'll simply state that the likelihood of each total appears as follows:
  • 2: 1/36
  • 3: 2/36
  • 4: 3/36
  • 5: 4/36
  • 6: 5/36
  • 7: 6/36
  • 8: 5/36
  • 9: 4/36
  • 10: 3/36
  • 11: 2/36
  • 12: 1/36


Before factoring in the consolation prize, we can express the value of x as:

x = (1/36)*(1000 + x) + (2/36)*(600 + x) + (3/36)*(400 + x) + (4/36)*(300 + x) + (5/36)*(200 + x) + (5/36)*(200 + x) + (4/36)*(300 + x) + (3/36)*(400 + x) + (2/36)*(600 + x) + (1/36)*(1000 + x)

Next, multiply both sides by 36:

36x = (1000 + x) + 2*(600 + x) + 3*(400 + x) + 4*(300 + x) + 5*(200 + x) + 5*(200 + x) + 4*(300 + x) + 3*(400 + x) + 2*(600 + x) + (1000 + x)

36x = 11,200 + 30x

6x = 11,200

x = 11,200/6 = 1866.67.

Next, the value derived from the consolation prize is calculated as 700*(6/36) = 116.67.

Thus, the average win of the bonus is 1866.67 + 116.67 = 1983.33.

What is the anticipated number of random samples drawn from a uniform distribution between 0 and 1 needed for their sum to exceed 1?

anonymous

Answer:

e=2.718281828..
Solution:
Here is solution .

How can I compute the possible combinations of wins for slot games that feature 'Multiway wins'? For context, let's say I have access to the reel strips.

James from Vermont

For the benefit of other readers, games with 'Multiway' wins encompass all conceivable pay-lines. However, the game only compensates players once per winning symbol combination. Playlines terminate when a reel is encountered with no winning symbols present.

Let's consider a case involving a five-reel game with three visible rows. All winning combinations align to the left. Imagine the player lands a winning symbol on reels 1, 2, 3, and 5. In this scenario, the player would receive payment only once for three of that symbol. Even though there are 9 potential ways to connect reels 4 and 5, the pay-lines cease at reel 3 in this context.

Now, let's say the player achieved the same winning symbol occurrence as follows on each reel:

  • Reel 1: 2
  • Reel 2: 1
  • Reel 3: 3
  • Reel 4: 2
  • Reel 5: 1


The player would receive payment for 2×1×3×2×1 = 12 distinct pay-lines.

If the player filled the entire screen with the same winning symbol, their payout would amount to 3.5=243 pay-lines.

Now, let's proceed to the answer. We will consider wins that consist of 3 to 5 symbols only.

Let's define some terminology:

  • tx= total reel stops on reel x.
  • nx= total quantity of the winning symbol on reel x.
  • px= locations on reel strips x where no winning symbol is visible.


  • For reel 3 the answer is 33× n1× n2× n3× p4× t5.

    For reel 4 the answer is 34× n1× n2× n3× n4× p5.

    For reel 5 the answer is 35× n1× n2× n3× n4× n5.